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Unexpected phenomena for equilibrium measures

Photo of Marcel Riesz
Marcel Riesz (1886 -1969)

This post is about Riesz energy problems, a subject that I like to explore with Edward B. Saff (Vanderbilt University, USA) and Robert S. Womersley (UNSW Sydney, Australia).

Riesz kernel. For 2<s<d, the Riesz s-kernel in Rd  is Ks:={1s||sif s0log||if s=0. We recover the Coulomb or Newton kernel when s=d2. This definition of the s-kernel allows to pass from Ks to K0 by removing the 1/s singularity at s=0, namely, for x0, log|x|=lims0s0|x|s1s0=lims0s0(1s|x|s1s).

Riesz energy. For 2<s<d, the Riesz energy of a probability measure μ on Rd is Is(μ):=Ks(xy)dμ(x)dμ(y)=(Ksμ)dμ. The Riesz energy is strictly convex and lower semi-continuous for the weak convergence of probability measures with respect to continuous and bounded test functions. This convexity is related to the Bochner positivity of Ks, which is a nice observation from harmonic analysis.

Equilibrium measure. The equilibrium measure on a ball BR:={xRd:|x|R} is
μeq=argminμsupp(μ)BRIs(μ).

Riesz original problem (1938). Equilibrium measure on BR when d2 :
μeq={σRif 2<sd2Γ(1+s2)Rsπd2Γ(1+sd2)1BR(R2|x|2)ds2dxif 0d2<s<d where σR is the uniform distribution on the sphere {xRd:|x|=R} of radius R.

The proof relies on the following integral formula for the variational characterization : |y|R|xy|s(R2|y|2)ds2dy=πd2+1Γ(d2)sin(π2(ds)),xBR The Riesz proof of this integral formula involves in turn a Kelvin transform and a reduction to the planar case. It can be found in detail in the Appendix of the book by Landkof (1972), and also with even more details in our 2022 JMAA article. A generalization (and a new proof) was published in 2017 by Dyda, Kuznetsov, and Kwaśnicki by using Fourier analysis.

The result expresses a threshold phenomenon : the support condensates on a sphere when s passes the critical value d2 (Coulomb). Our main finding is that this Riesz problem admits a full space extension in which we replace the ball support constraint with an external field. We show that a new threshold phenomenon occurs, related to the strenght of the external field.

External field equilibrium problem. The energy with external field V on Rd is defined by I(μ)=Is,V(μ):=[Ks(xy)+V(x)+V(y)]dμ(x)dμ(y)
and the associated equilibrium measure μeq=argminμI(μ) The Frostman or Euler-Lagrange variational characterization of μeq reads Ksμ+V{=cquasi-everywhere on supp(μ)cquasi-everywhere outside supp(μ) Quasi-everywhere means except on a set that cannot carry a probability measure of finite energy. By taking V=1BcR we recover the Riesz problem on the ball mentioned previously.

Coulomb case : s=d2. The kernel Kd2 is a Laplace fundamental solution :
ΔKd2D=cdδ0,withcd=|Sd1|.Also, restricted to the interior of supp(μeq),
μeqD=ΔVcdIn particular, if V=||α, α>0, then
μeq=α(α+d2)||α21BRdxwithR=(1α)1d2+α. The proof relies crucially on the local nature of the Laplacian.

At this point we observe that the formula ΔKu=cd,uKu+2,cd,u:=d2u suggests to apply iteratively Δ to reach the case s=d2n for an arbitrary positive integer n.

Findings for the iterated Coulomb case s=d2n,n=1,2,3,. Then, restricted to the interior of μeq, in the sense of distributions,
μeqD=ΔnVcdCd,n,whereCd,n:=(1)n1n2k=0cd,s+2k=(1)n1(2n2)!!. In particular : if s=d4 and V=||α, α2, then Cd,2<0 while ΔV=α(α+d2)||α20 and thus μeq is necessarily singular! Actually the case s=d4 can be analyzed completely, and this analysis reveals the singularity when α2 as well as a threshold condensation to this singular support when α reaches the critical value 2.

Findings when s=d4. Suppose that V=γ||α, γ>0,α>0.

  • Let d4 and s=d40.
    • If α2 then μeq=σR (indeed it is singular!) where R=(2(s+4)αγ)1α+s
    • If 0<α<2 then (mixture!) μeq=βfmd+(1β)σR where
      β=2αs+2, f=α+sRα+s|Sd1|1BR, R=(2(α+s+2)αγ)1α+s
  • Let d=3 and s=d4=1 (non-singular kernel!).
    • If 0<α<1, then μeq does not exist (blowup)
    • If α=1 and γ1, then μeq=δ0 (collapse).
    • If α>1, then μeq is as above (mixture).

In contrast, there is no threshold condensation phenomenon when s=d3.

Findings when s=d3. Suppose that V=γ||α, γ>0,α>0.

  • If s=d3 and α=2 then μeq=Γ(s+42)πs+42Rs+21BRR2||2dx where R=(π4γΓ(s+42)Γ(s+52))1s+2
  • This is also μeq for s=d1 on BR with this R.

Methods of proof.

  • Frostman or Euler-Lagrange variational characterization
  • Applying Laplacian on support of μeq
  • Rotational invariance and maximum principle
  • Dimensional reduction with Funk-Hecke formula
  • Orthogonal polynomials expansions
  • Integral formulas and special functions

Challenges.

  • Super-harmonic kernel and sub-harmonic external field
  • Non-locality of fractional Laplacian

Selected Open Problems.

  • When s=d3 with α2, we conjecture that the support of the equilibrium measure is a ball if 0<α<2 and a full dimensional shell (annulus) if α>2
  • When s=d6, it could be that the support of the equilibrium measure is disconnected
  • Other norms in kernel and external field

Marcel Riesz (1886 - 1969) is the young brother of Frigyes Riesz (1880 - 1956). I do not known if Naoum Samoilovitch Landkof (1915 - 2004) has ever met in person Marcel Riesz. Landkof was a student of Mikhaïl Alekseïevitch Lavrentiev (1900 - 1980),  who gave his name to the Lavrentiev phenomenon in the calcul of variations. Landkof was an expert in potential theory. He advised Vladimir Alexandrovich Marchenko (1922 - ), famous notably for his findings on random operators and matrices with his student Leonid Pastur (1937 - ).

Further reading.

Photo of Naoum Samoilovitch Landkof
Naoum Samoilovitch Landkof (1915 - 2004)
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